Paper A is in the form of a square of side 130mm. Four quadrants of diameter 14mm is cut from the four corners of the square. Paper B is in the form of a rectangle whose one side is 150mm and this si…

Question

Paper A is in the form of a square of side 130mm. Four quadrants of diameter 14mm is cut from the four corners of the square. Paper B is in the form of a rectangle whose one side is 150mm and this side is 20% more than the shorter side. Two semicircles of diameter equal to the smaller side of the rectangle is cut from both the edges of the rectangle. By what percent is the remaining area of paper B more or less than that of paper A?

PYQPulse · Accepted Answer

3. 61.3% less

PYQPulse · Answer

Explanation: 3 Detailed solution: For paper A: Area = Area of square - 4*Area of quadrant. Radius = 14/2 = 7mm Required area = (130*130) - area of circle of radius 7mm Required area = 16900 - 22/7 *7*7 Area = 16746 m² For paper B: Length of paper= 150mm Breadth of paper = 150/1.2 = 125mm Radius of semi circle = 125/2 = 62.5mm Remaining area = 150*125 - 62.5*62.5*22/7 = 18750 - 12276.8 = 6473.2 Required percentage = (16746-6473.2)*100/16746 = 61.3% less

Answer: C. 3. 61.3% less

Explanation

Answer: C. 3. 61.3% less

Explanation