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  9. Q108

RBI Grade B Officer (General / DEPR / DSIM) 2023 · Question 108 of 260

A man fell down from his boat at point 'A' which was 64 km away in downstream from a rescue boat which started travelling immediately for his rescue. Till the time, the rescue boat reached point 'A', the man travelled with help of stream only. As soon as the boat reached the point 'A', the man started swimming towards the boat such that his speed in still water is 5 km/h and the boat rescued him after 48 minutes after it reached point 'A'. The speed of the stream is 60% of that of the rescue boat in still water. Find the total distance covered by the rescue boat in the time it meets the man.

Speed, Time & Distance

  1. A1. 88 km
  2. B2. 108 km
  3. C3. 96 kmCorrect
  4. D4. 124 km
  5. E5. 120 km

Answer: C. 3. 96 km

Explanation

3 Detailed solution: Let the speed of the rescue boat = '10x' km/h Then, speed of the stream = 10x X 0.6 = '6x' km/h So, downstream speed of the boat = 10x + 6x = '16x' km/h So, time taken by the boat to reach the point where the man fell = (64/16x) = (4/x) hours So, distance travelled by the man who fell in (4/x) hours = (4/x) X 6x = 24 km Now, distance between the boat and the man = 24 km Relative speed of the boat w.r.t the man = 16x + (5 - 6x) = (10x + 5) km/h According to the question, {24/(10x + 5)} = (48/60) = 0.8 Or, 24 = 8x + 4 So, x = (20/8) = 2.5 So, downstream speed of the boat = 16 X 2.5 = 40 km/h So, total distance covered by the boat = 64 + 0.8 X 40 = 64 + 32 = 96 km

Source: RBI Grade B 2023 – Phase 1 recollected questions with answer key (EduTap compilation) · memory-based

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