Direction: In the given question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. I. 2x² + 5x + 3 = 0. II. 2y² – 7y + 6 = 0.

Question

PYQPulse · Accepted Answer

if x < y

PYQPulse · Answer

Explanation: First equation: 2x² + 5x + 3 = 0 ⇒ 2x² + 2x + 3x + 3 = 0 ⇒ 2x(x + 1) + 3(x + 1) = 0 ⇒ x = –1 or –3/2. Second equation: 2y² – 7y + 6 = 0 ⇒ 2y² – 4y – 3y + 6 = 0 ⇒ 2y(2y – 4) – 3(2y – 4) = 0 ⇒ y = 2 or 3/2. ⇒ When x = –1, y > x. When x = –3/2, y > x. ∴ y > x.

Direction: In the given question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. I. 2x² + 5x + 3 = 0. II. 2y² – 7y + 6 = 0.

Answer: C. if x < y

Explanation

Direction: In the given question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. I. 2x² + 5x + 3 = 0. II. 2y² – 7y + 6 = 0.

Answer: C. if x < y

Explanation