IBPS PO 2018 · Question 48 of 98
Quadratic Equations
First equation: 3x² – 7x + 4 = 0 ⇒ 3x² – 3x – 4x + 4 = 0 ⇒ x(3x – 4) – 1(3x – 4) = 0 ⇒ x = 1 or 4/3. Second equation: 2y² – 3y + 1 = 0 ⇒ 2y² – 2y – y + 1 = 0 ⇒ 2y(y – 1) – 1(y – 1) = 0 ⇒ y = 1 or 1/2. ⇒ When x = 1, x > y or x = y. When x = 4/3, x > y. ∴ x ≥ y.
Source: IBPS PO 2018 Prelims Memory-Based Test 13-Oct-2018 Shift 1 (Prepp) · memory-based
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