SSC MTS & Havaldar 2011 · Question 37 of 74
Let side of equilateral triangle = a and side of regular hexagon = s According to ques, => 3a = 6s => a = 2s Now, ratio of the area of the triangle to that of the hexagon : 3 =( 2 332 4a ) : ( 2s ) 1 => 2 2 2 (2s) = 3s => 2 : 3
Source: Solved SSC MTS 20 February 2011 Shift 1 Paper with Solutions · reliable-secondary
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