SSC CHSL 2020 · Question 66 of 91
Trigonometry
Given: 4 2 ⇒ ? = (x +x +1) (x2 +x+1) Formula: a 2- b 2= (a + b)(a - b) Calculation: ⇒ ? = (x 4+ 2x 2+ 1 - x 2)/(x 2+ x + 1) ⇒ ? = [(x 2+ 1) - x 2]/(x 2+ x + 1) ⇒ ? = [(x 2+ 1 - x)(x 2+ 1 + x)]/(x 2+ x + 1) ⇒ ? = x 2- x + 1 2 4 2 ∴ (x +x +1) (x2 +x+1) = x - x + 1
Source: SSC CHSL 2020 (Tier-I) Prev. Year Paper (04-Aug-2021) (Shift 1) — prepp.in solved paper · reliable-secondary
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