Testwala logoTestwala
HomeMocksPracticePYQsDashboard
Testwala logoTestwala

Timing-accurate mock tests and PYQs for SSC, Banking and Railway exams — so the real paper feels like a revision.

Exams

  • SSC exams
  • Banking exams
  • Railway exams
  • All exams

Practice

  • Practice questions
  • Mock test series
  • Sectional tests
  • Year-wise PYQs
  • Performance analytics

Company

  • About us
  • Help Centre
  • Pricing
  • Sign in

Legal

  • Privacy Policy
  • Terms of Service

Contact

  • hello@testwala.co.in
  • Telegram
  • +91 62816 87760

Practice interface modeled on the official exam pattern — not the official examination. Testwala is not affiliated with the Staff Selection Commission, IBPS, SBI, RBI, NABARD, SEBI or Indian Railways.

© 2026 Testwala. All rights reserved.

Built for aspirants, by aspirants.

HomeMocksPracticeStats
  1. Home
  2. ›
  3. PYQs
  4. ›
  5. SSC CHSL
  6. ›
  7. 2020
  8. ›
  9. Q48

SSC CHSL 2020 · Question 48 of 91

One-quarter of a circular pizza of diameter 28 cm was removed from the whole pizza. What is the perimeter (in cm) of the remaining pizza? (Take π = 22/7)

Mensuration

  1. A88
  2. B80
  3. C66
  4. D94Correct

Answer: D. 94

Explanation

Given: Diameter of pizza = 28cm Formula: Circumference of circle = πd Calculation: Radius of pizza = 28/2 = 14cm Total circumference of pizza = 22/7 × 28 = 88cm Circumference of 3/4 of pizza = 88 × 3/4 = 66cm ∴ Perimeter of remaining pizza = 66 + 14 + 14 = 94cm

Source: SSC CHSL 2020 (Tier-I) Prev. Year Paper (04-Aug-2021) (Shift 1) — prepp.in solved paper · reliable-secondary

← Q47View full paper (91 questions)Q49 →

Practice the full SSC CHSL 2020 paper

Timed test with all 91 questions, just like the real exam.

Start test