DIRECTIONS: In questions no. 96 to 100, you have a brief A chord 12 cm long is drawn in a circle of diameter 20 cm. The distance of the chord from the centre is

Explanation

OE = ? O 10 10 C D 10 B A 6 E 6 Now, AE = EB = 6cm (The line drawn from centre of circle to the chord bisect the chord) In DOAE, By phythagoras theorem (OA)2 = (OE)2 + (AE)2 Þ (10)2 = (OE)2 + (6)2 100 – 36 = (OE)2 = 64 = OE2 Þ = OE 8 cm 2013 Solved Paper æ ö 10 - x 1 100 ç ÷ 81 = x – 10% of x Þ è ø 81 = 9 810 Þ = x x 10 9 \ x = 90 marks