DIRECTIONS: In questions no. 96 to 100, you have a brief From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to diameter of the circle, then ÐAPB is

Explanation

( ) ^ ^ QOA PA & OB PB A r q1 P O q2 r 2r B r 1 = \ In D OAP, sinq1 = r 2 2 q = ° sinq1 = sin 30° Þ 1 30 r 1 = Similary, in DOBP, sinq2 = r 2 2 sinq2 = sin 30° Þ q2 = 30° Ð = q + q = °+ ° = ° \ APB 30 30 60 1 2 2013 Solved Paper æ ö 10 - x 1 100 ç ÷ 81 = x – 10% of x Þ è ø 81 = 9 810 Þ = x x 10 9 \ x = 90 marks