SSC CHSL 2012 · Question 123 of 202
Let the side of square = ‘x’ Area of square = x2 New length of rectangle = 130 x 100 New Breadth of rectangle = 120 x 100 130 120 2 ´ ´ x Hence, Area of so formed rectangle = 100 100 156 x 2 = 100 Therefore, area of rectangle exceeds the area of square by 56%
Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary
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