SSC CHSL 2012 · Question 122 of 202
= = = k say + + + b c c a a b So, x = k (b + c) Þ x – y = k (b + c) – k (c + a) = k (b – a) y = k (c + a) Þ y – z = k (c + a) – k (a + b) = k (c – b) z = k (a + b) = z – x = k (a + b) – k (b + c) = k (a – c) So,check option (a) - - - x y y z z x = = - - - b a c b a c ( ) ( ) ( ) - - - k b a k c b k a c = = - - - b a c b a c k = k = k option (a) is true.
Source: SSC CHSL Solved Paper 04-11-2012 (Disha Publications) · reliable-secondary
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