If a man runs at 6 kmph from his house, he misses the train at the station by 8 minutes. If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the d…

Question

If a man runs at 6 kmph from his house, he misses the train at the station by 8 minutes. If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the distance of station from his house? (in km)

PYQPulse · Accepted Answer

$$3\frac{3}{4}$$

PYQPulse · Answer

Explanation: Let the distance of the station from the house of the person = $$x$$ km Difference of time = 8 + 7 = 15 minutes = $$\frac{1}{4}$$ hr Since, Time = $$\frac{Distance}{Speed}$$ $$	herefore \frac{x}{6} - \frac{x}{10} = \frac{1}{4}$$ => $$\frac{10x - 6x}{60} = \frac{1}{4}$$ => $$\frac{2x}{30} = \frac{1}{4}$$ => $$x = \frac{15}{4} = 3\frac{3}{4}$$ km

If a man runs at 6 kmph from his house, he misses the train at the station by 8 minutes. If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the distance of station from his house? (in km)

Answer: D. $$3\frac{3}{4}$$

Explanation

If a man runs at 6 kmph from his house, he misses the train at the station by 8 minutes. If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the distance of station from his house? (in km)

Answer: D. $$3\frac{3}{4}$$

Explanation