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MPSC State Service 2020 · CSAT · Question 25 of 77

Consider a satellite in circular orbit around the Earth at a distance R from the Earth՚s center. The area that the satellite sweeps out as it moves through an angle ϕ is given by A = R2ϕ⟋2. Kepler՚s second law implies that the time that it takes for the satellite to move through 2ϕ is:

Reading Comprehension

  1. Adouble the time that is takes to move through ϕ.Correct
  2. Bhalf the time that it takes to move through ϕ.
  3. Cthe square of the time that it takes to move through ϕ.
  4. Dequal to the time that it takes to move through ϕ.

Answer: A. double the time that is takes to move through ϕ.

Explanation

With the constant-force approximation the transit time equals the free-fall time phi (the passage's notation): option (c).

Source: MPSC Rajyaseva Prelims 2020 – CSAT Paper II (Set C), official paper

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