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  9. Q24

MPSC State Service 2020 · CSAT · Question 24 of 77

The amount of energy needed to move a rocket having mass m from the surface of the Earth to a distance R from the Earth՚s center is E = Re GmM e ( 1 − 1) R . What is the minimum velocity, the rocket must have in order to completely escape the Earth gravitational field? 1 2Gm ( )

Reading Comprehension

  1. A( Re ) 2 1 2Gme ( )
  2. B( Re ) 2 (1)Correct
  3. C( 2 g h ) 2 ( 12 )
  4. D( 2 m G R e)

Answer: B. ( Re ) 2 (1)

Explanation

Escape velocity from Earth's surface is sqrt(2GMe/Re): option (b).

Source: MPSC Rajyaseva Prelims 2020 – CSAT Paper II (Set C), official paper

← Q23View full paper (77 questions)Q25 →

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