ibps-so 2023 · Question 102 of 323
ATQ, Given: Distance (A–B) = 25.5 km Time downstream = 85 min = 17/12 hr Downstream speed Speed in still water = 4 × stream speed So, 5v = 18⟹v = 3.6 km/h Upstream speed 4v − v = 3v = 10.8 km/h Distance in 4.9 hr upstream 10.8 × 4.9 = 52.92 km
Source: IBPS SO Prelims Memory Based 2023 (AFO/IT/HR/Marketing) - ixamBee · memory-based
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