ibps-so 2023 · Question 101 of 323
Let the speed one train be x m/s and the speed of the second train be y m/s. Length of the first train = Speed × Time = 26x Length of second train = Speed × Time = 16y So, {(26x + 16y)/(x+y)} = 18 ⇒ 26x + 16y = 18x + 18y ⇒ 8x = 2y Therefore, x:y = 1:4
Source: IBPS SO Prelims Memory Based 2023 (AFO/IT/HR/Marketing) - ixamBee · memory-based
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