ibps-so 2020 · Question 270 of 351
Let the length of platform = x m and speed of man = y m/sec 99 × 5/18 = (440 + x)/40 . c o 1100 = 440 + x x = 660 m so speed of man = y = 660/2 × 60 = 5.5 m/sec
Source: IBPS SO Prelims Memory Based 2020 (IT/AFO/HR/Marketing) - ixamBee · memory-based
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