A is 40% more efficient than B and both together can complete a work in (85/8) days. If A work for first 5 days alone and remaining work complete by B, then find in how many days total work will be c…

Question

A is 40% more efficient than B and both together can complete a work in (85/8) days. If A work for first 5 days alone and remaining work complete by B, then find in how many days total work will be competed?

Testwala · Accepted Answer

23.5 days

Testwala · Answer

Explanation: Let efficiency of B = 5x unit/day So, efficiency of A = 5x × 140% = 7x unit/day Total work = (7x + 5x) x 85/8 = 127.5x unit Total work done by A in 5 days = 7x × 5 = 35x unit Total required days = 5 + [127.5x – 35x]/5x = 23.5days e e

A is 40% more efficient than B and both together can complete a work in (85/8) days. If A work for first 5 days alone and remaining work complete by B, then find in how many days total work will be competed?

Answer: E. 23.5 days

Explanation

A is 40% more efficient than B and both together can complete a work in (85/8) days. If A work for first 5 days alone and remaining work complete by B, then find in how many days total work will be competed?

Answer: E. 23.5 days

Explanation