A boat travelled 𝟑𝒙 𝟓 km in downstream and 𝟐𝒙 𝟓 𝒌𝒎 in upstream. Speed of boat in still water is 12 km/hr and speed of stream is 8 km/hr and time taken by boat to cover given distance in upstream is 14 hours more than of time taken by boat to cover given distance in downstream. Find the total distance travelled in downstream?

Explanation

Distance travelled by boat in downstream = 3𝑥 5 km ATQ, 2𝑥 5(4) − 3𝑥 5(20) = 14 10𝑥−3𝑥 100 = 14 𝑥 = 200 Distance covered in downstream = 200 × 3 5 = 120 𝑘𝑚 Sol (36-40) Let Y be 100x. Cost price of article bought by A = 100x 83 www.bankersadda.com | Adda247 App Cost price of article bought by B = 150x Cost price of article bought by C = 200x Marked price of article by A= 100x + 100 Selling price of article by A = 100x + 40 Discount = 100x + 100 – (100x + 40 ) = 100 – 40 = 60 Cost price of article B = 150x = 5 (60) 2 = x For A, Cost price = Rs 200 = Y, selling price = 240, marked price = 300 d% = 60/300 x 100= 20% profit % = 20% Cost price of article bought by B = Rs 300 Cost price of article bought by C = Rs 400