I. x2 + 9x + 14 = 0 II. y2 + 15y + 56 = 0

Explanation

I. x2 + 9x + 14 = 0 ⇒ x 2 + 2x + 7x + 14 = 0 ⇒ x(x + 2) + 7(x + 2) = 0 ⇒ (x + 2)(x + 7) = 0 ⇒ x = −2, −7 II. y2 + 15y + 56 = 0 ⇒ y 2 + 8y + 7y + 56 = 0 ⇒ y(y + 8) + 7(y + 8) = 0 ⇒ (y + 8) (y + 7) = 0 ⇒ y = −8, −7 Hence, x ≥ y. Alternate Method: If signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve. So, roots of first equation = x = -2, -7 So, roots of second equation = y = -8, -7 After comparing we can conclude that x ≥ y. IBPS RRB Scale I 2021 Prelims Memory Based Paper