I. 2x2 + 17x + 35 = 0 II. y2 + 10y + 25 = 0

Explanation

I. 2x2 + 17x + 35 = 0 ⇒ 2x2 + 10x + 7x + 35 = 0 ⇒ 2x(x + 5) + 7(x + 5) = 0 ⇒ (2x + 7) (x + 5) = 0 ⇒ x = −7/2, −5 II. y2 + 10y + 25 = 0 ⇒ y 2 + 5y + 5y + 25 = 0 ⇒ y(y + 5) + 5(y + 5) = 0 ⇒ (y + 5) (y + 5) = 0 ⇒ y = −5,-5 Hence, x ≥ y. IBPS RRB Scale I 2021 Prelims Memory Based Paper Alternate Method: if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve. So, roots of first equation = x = -7/2, -5 So, roots of second equation = y = -5, -5 After comparing we can conclude that x ≥ y.