In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer: I. 2x² – 14x + 24 = 0 II. y² + 30y + 224 = 0

Question

PYQPulse · Accepted Answer

x > y

PYQPulse · Answer

Explanation: Equation I. 2x² – 14x + 24 = 0 ⇒ 2x² – 8x – 6x + 24 = 0 ⇒ 2x(x – 4) – 6(x – 4) = 0 ⇒ (2x – 6)(x – 4) = 0 ⇒ x = 3 or x = 4. Equation II. y² + 30y + 224 = 0 ⇒ y² + 14y + 16y + 224 = 0 ⇒ y(y + 14) + 16(y + 14) = 0 ⇒ (y + 14)(y + 16) = 0 ⇒ y = –14 or y = –16. Since x = 3 or 4 and y = –14 or –16, ∴ x > y.

In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer: I. 2x² – 14x + 24 = 0 II. y² + 30y + 224 = 0

Answer: A. x > y

Explanation

In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer: I. 2x² – 14x + 24 = 0 II. y² + 30y + 224 = 0

Answer: A. x > y

Explanation