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  9. Q7

UKPSC PCS 2012 · Question 7 of 78

A man walks 1 km. towards East, then turns to South and walks 5 km. Again he turns to East and walks 2 km. Then he turns to North and walks 9 km. How far is he from the starting point ?

Reasoning

  1. A2 km
  2. B3 km
  3. C5 kmCorrect
  4. D9 km

Answer: C. 5 km

Explanation

Net displacement is 3 km east and 4 km north: sqrt(9+16) = 5 km.

Source: UKPSC 2012 Prelims CSAT Paper-II (adda247/studyfry PDF), exam held 30 Nov 2014

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