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  9. Q39

UKPSC PCS 2012 · Question 39 of 78

The number of integers between 1 and 100 (including both) which are fully divisible by 3 or 5 is :

Quant

  1. A47Correct
  2. B49
  3. C51
  4. D53

Answer: A. 47

Explanation

floor(100/3)+floor(100/5)-floor(100/15) = 33+20-6 = 47.

Source: UKPSC 2012 Prelims CSAT Paper-II (adda247/studyfry PDF), exam held 30 Nov 2014

← Q38View full paper (78 questions)Q40 →

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