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TNPSC Group-I 2021 · Question 137 of 148

Find the HCF of (x^2y + xy^2) and (x^2 + xy).

Aptitude - Algebra

  1. Ax + y
  2. Bxy
  3. Cx(x + y)Correct
  4. Dx^2 + y^2

Answer: C. x(x + y)

Explanation

x^2y + xy^2 = xy(x+y); x^2 + xy = x(x+y). HCF = x(x+y).

Source: TNPSC Group-I Prelims (held 3 Jan 2021) - official paper via examrace.com

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