TNPSC Group-I 2021 · Question 117 of 148
Aptitude - Series
1^3+2^3+...+k^3 = [k(k+1)/2]^2 = 44100 = 210^2, so k(k+1)/2 = 210, giving k = 20.
Source: TNPSC Group-I Prelims (held 3 Jan 2021) - official paper via examrace.com; solution cross-checked with Appolo Study Centre solutions
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