TGPSC Group-I 2024 · Question 129 of 144

Let A = 20% of x + 80% of y and B = 70% of x + 30% of y where x is greater than y. If k% of (x – y) is (B – A), then what is the value of k ?

Mental Ability

Answer: D. 50

B − A = 50% of (x − y), so k = 50: 20%→70% is +50% of x, 80%→30% is −50% of y, and since x > y, B − A = 50%·(x − y).

Source: TGPSC Group-I Preliminary Test 2024 official question paper booklet (held 9 Jun 2024, TEST 224) with Preliminary Key (MASTER), via Adda247

Practice the full TGPSC Group-I 2024 paper

Timed test with all 144 questions, just like the real exam.

TGPSC Group-I 2024 · Question 129 of 144

Mental Ability

B − A = 50% of (x − y), so k = 50: 20%→70% is +50% of x, 80%→30% is −50% of y, and since x > y, B − A = 50%·(x − y).

Source: TGPSC Group-I Preliminary Test 2024 official question paper booklet (held 9 Jun 2024, TEST 224) with Preliminary Key (MASTER), via Adda247

Practice the full TGPSC Group-I 2024 paper

Timed test with all 144 questions, just like the real exam.