SSC Selection Post (Phase XIV) 2025 · Question 250 of 284
geometry
Given: Height (h) = 200 m Angles = 30∘ , 60∘ Solution: Copyright © 2026 Adda247 Let distance of cars from base be d1 and d2 . d1 = h cot 30∘ = 200 3 200 d2 = h cot 60∘ = 3 Distance between cars = d1 − d2 200 = 200 3 − 3 1 = 200 ( 3 − ) 3 3−1 400 = 200 ( )= m 3 3 Final Answer 400 m 3
Source: SSC Selection Post (Graduation) Similar Paper (Held on 25 Jul 2025 S3) — Adda247/CareerPower memory-based reconstruction with answers and solutions · memory-based
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