SSC Selection Post (Phase XIV) 2025 · Question 248 of 284
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Given: 1 x+ =4 x+5 Formula Used: 1 1 If k + = a, then k 3 + 3 = a3 − 3a k k Solution: Add 5 to both sides to make the term (x + 5) : 1 (x + 5) + =4+5 x+5 1 (x + 5) + =9 x+5 1 Let k = x + 5. Then k + = 9. k 1 We need to find k 3 + . k3 1 k3 + 3 = 93 − 3(9) k = 729 − 27 = 702 Final Answer 702
Source: SSC Selection Post (Graduation) Similar Paper (Held on 25 Jul 2025 S3) — Adda247/CareerPower memory-based reconstruction with answers and solutions · memory-based
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