SSC Selection Post (Phase XIV) 2025 · Question 160 of 284
geometry
Given: ∘ sin 2A = cos(A − 45 ). Formula Used: ∘ sin θ = cos(90 − θ). Solution: cos(90∘ − 2A) = cos(A − 45∘ ) ∘ 90 − 2A = A − 45∘ ∘ 3A = 135 ∘ A = 45 Final Answer So the correct answer is (b)
Source: SSC Selection Post (Higher Secondary) Similar Paper (Held on 25 Jul 2025 S2) — Adda247/CareerPower memory-based reconstruction with answers and solutions · memory-based
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