SSC MTS & Havaldar 2016 · Question 141 of 162
⇒ Distance travelled in 3 hours = 3 × 100 = 300 km ⇒ Distance travelled in remaining 2 hours = 2 × 120 = 240 km ⇒ Average speed = Total distance/total time taken ⇒ Average speed = (300 + 240)/5 = 540/5 ∴ Average speed = 108 k/hr
Source: SSC MTS 2016 re-exam (held 10-Oct-2017 Shift 1) paper with key+explanations, via prepp.in · reliable-secondary
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