SSC MTS & Havaldar 2016 · Question 134 of 162
⇒ Let (2/3)P = (4/5)Q = (3/2)R = k ⇒ (2/3)P = k, (4/5)Q = k, (3/2)R = k ⇒ P = 3k/2, Q = 5k/4, R = 2k/3 ⇒ P : Q : R = 3k/2 : 5k/4 : 2k/3 ⇒ LCM (2, 4, 3) = 12 ⇒ P : Q : R = (3k/2) x 12 : (5k/4) x 12 : (2k/3) x 12 ⇒ P : Q : R = 18k : 15k : 8k ∴ P : Q : R = 18 : 15 : 8
Source: SSC MTS 2016 re-exam (held 10-Oct-2017 Shift 1) paper with key+explanations, via prepp.in · reliable-secondary
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