SSC MTS & Havaldar 2014 · Question 49 of 82

Length of each equal side of an isosceles triangle is 10 cm and the included angle between those two sides is 45∘. Find the area of the triangle.

A25 2Correct
B35 2
C5 2
D15 2

Answer: A. 25 2

Explanation

1 Area of isosceles triangle = 2× (a)2 × sin(θ), where a is one of the equal sides and θ is the angle between them. 1 => Area = 2 × (10)2 × sin(45∘) 1 = 50 × 2 = 25 2 cm2

Source: Solved SSC MTS 23 February 2014 Shift 1 Paper with Solutions · reliable-secondary

Practice the full SSC MTS & Havaldar 2014 paper

Timed test with all 82 questions, just like the real exam.

Start test