SSC MTS & Havaldar 2011 · Question 31 of 74

The sum of the square of 3 consecutive positive numbers is 365. The sum of the numbers is

A30
B33Correct
C36
D45

Answer: B. 33

Explanation

Let the 3 consecutive positive numbers = (x − 1), (x), (x + 1) According to ques, => (x − 1) 2 + (x)2(x + 1) 2 = 365 => (x2 − 2x + 1) + (x2 ) + (x2 + 2x + 1) = 365 => 3x2 + 2 = 365 => 3x2 = 365 − 2 = 363 363 => x2 = 3 = 121 => x = 121 = 11 ∴ Sum of numbers = (x − 1) + (x) + (x + 1) = 3x = 3 ×11 = 33

Source: Solved SSC MTS 20 February 2011 Shift 1 Paper with Solutions · reliable-secondary

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