SSC MTS & Havaldar 2011 · Question 16 of 74
Father was three times his son's present age when he was born, F - S = 3S F = 4S (or) 4S = 48 (or) S = 12 Now, age of son before 4 years = 8 years. Hence, option B is the correct answer.
Source: Solved SSC MTS 20 February 2011 Shift 1 Paper with Solutions · reliable-secondary
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