The income of X is 20% less than the income of Y, and the income of Z is 35% less than the combined incomes of X and Y. By what percentage is the income of Z more than that of X?

Explanation

Given: The income of X is 20% less than the income of Y. The income of Z is 35% less than the combined incomes of X and Y. Calculation: According to Question, Income of X/Income of Y = 80/100 Income of Z = Income of (X + Y) × 65/100 ⇒ Z = (80 + 100) × 65/100 ⇒ Z = 117 So X = 80, Y = 100 and Z = 117 Income of Z = 117 is more than that of X = 80 by 37. ⇒ (37/80) × 100 ⇒ 46.25% ∴ The Required answer is 46.25%.