Vessels A and B contain solutions of acid and water. The ratio of acid and water in vessel A is 7 : 5 and that in vessel B is 11 : 13. Four liters of solution from vessel A is mixed with 5 liters of solution from vessel B. What is the ratio of acid and water in the mixture?

Explanation

Given: The ratio of acid and water in vessel A is 7 : 5 and that in vessel B is 11 : 13. 4 liters of solution from vessel A are mixed with 5 liters of solution from vessel B. Calculation: Vessel A, Quantity of acid = Quantity of water = 7 12 ​ 5 12 ×4= ​ ×4= 7 3 ​ 5 3 ​ Now, Vessel B Quantity of acid = 11 24 Quantity of water = ×5= ​ 13 24 ​ ×5= 55 24 ​ 65 24 ​ The ratio of acid and water in the resulting solution [( 73 + 55 )] : [( 53 + 65 )] 24 24 ​ ⇒ 111 24 ​ ​ : 105 24 ​ ​ ​ ⇒ 111 : 105 = 37 : 35 ∴ The ratio of acid and water in the mixture is 37 : 35.