SSC GD Constable 2021 · Question 159 of 377
number-system
Given: The numbers are 6, 4 and 3 Closest number is 2495 Concept used: For this type of question, we use LCM of the given numbers and divide it with the closest divisible number which is given in the question Calculation: LCM of 6, 4 and 3 = 12 Now, By dividing 2495 with 12 we get 11 as the remainder So, least number required to get a fully divisible number is (12 - 1) = 1 ∴ Required number is 1.
Source: SSC GD Constable 2021 Prev. Year Paper (2021-11-23 Shift 1) English — Prepp (with solutions) · reliable-secondary
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