Find the least number that should be added to 1014 such that the resulting number can be divided by 3, 4, 5 and 6 , leaving no remainder.

Explanation

Given: The numbers are 3, 4, 5 and 6 Closest number is 1014 Concept used: For this type of question, we use LCM of the given numbers and divide it with the closest divisible number which is given in the question Calculation: LCM of 3, 4, 5, and 6 = 60 Now, By dividing 1014 with 60 we get 54 as the remainder So, least number required to get a fully divisible number is (60 - 54) = 6 ∴ Required number is 6.