SSC GD Constable 2012 · Question 64 of 95
From △ ACD, AD tan 60∘ = CD ⇒ AD = CD 3 From △ ABD, AD tan 45∘ = BD ⇒ AD = BD ⇒ AD = BC+CD AD (28) AD ⇒ AD = 60 + 3 AD ⇒ AD − 3 = 60 3 AD−AD ⇒ 3 = 60 AD( 3 − 1) = 60 3 60 3 AD = 3 −1 Rationalising above equation 60 3 3 +1 AD = 3 −1 × 3 +1 60 3 ( 3 +1) AD = 3 ∴ AD = 30( 3 + 3)
Source: Solved SSC GD 2012 Shift 1 Paper with Solutions — Testbook · reliable-secondary
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