SSC GD Constable 2011 · Question 24 of 97
1 Each angle of a regular Octagon = 8 (2n − 4)right angle where n=no. of sides 1 = 8 (2 × 8 − 4) × 90∘ 12×90 ∘ = 8 = 135∘ 180∘ =∏ ∏ 3∏ (13) ∏ 3∏ 135∘ = 180 × 135∘ = 4
Source: Solved SSC GD 2011 Paper with Solutions — Testbook · reliable-secondary
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