SSC GD Constable 2011 · Question 20 of 97

Inside a square ABCD, △BEC is an equilateral triangle. If CE and BD interesect at O, then ∠BOC is equal to

A60∘
B75∘Correct
C90∘
D120∘

Answer: B. 75∘

Explanation

In square ABCD, △ BEC is an equilateral triangle Each angle of an equilateral triangle is 60 ∘ ⇒ ∠ OCB = 60∘ 90 ∘ ∠ DBC = 2 = 45∘ ( ∵ BD is diagonal of ABCD) In △ OBC, ∠ OBC+∠ OCB+∠ BOC = 180∘ 60∘ + 45∘ + ∠BOC = 180∘ ∴ ∠BOC = 75∘

Source: Solved SSC GD 2011 Paper with Solutions — Testbook · reliable-secondary

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