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  9. Q17

SSC GD Constable 2011 · Question 17 of 97

All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm. BC = 7.5 cm. CD = 3 cm, then DA is

  1. A3.5 cm
  2. B4.5 cm
  3. C2.5 cm
  4. D1.5 cmCorrect

Answer: D. 1.5 cm

Explanation

Given : AB = 6 cm. BC = 7.5 cm. CD = 3 cm To find : DA = ? Solution : Tangents from the same point to a circle are equal in length. => AE = AH , BE = BF , CG = CF and DG = DH Adding above equations, we get : => (AE + BE) + (CG + DG) = (BF + CF ) + (AH + DH) => AB + CD = BC + DA => 6 + 3 = 7.5 + DA => DA = 9 − 7.5 = 1.5 cm => Ans - (D)

Source: Solved SSC GD 2011 Paper with Solutions — Testbook · reliable-secondary

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