SSC CHSL 2020 · Question 62 of 91
Average
Given: 1/5 of journey = 30kmph 1/4 of journey = 25kmph (1 - 1/5 - 1/4 = 11/20) of journey = 60kmph Formula: Average speed = Total distance/Total time Calculation: Let total distance of journey be a km. Time taken for 1/5 of journey = a/150 hours Time taken for 1/4 of journey = a/100 hours Time taken for 11/20 of journey = 11a/1200 hours Total time taken for a km = a/150 + a/100 + 11a/1200 = 31a/1200 hours ∴ Average speed = a/(31a/1200) = 38.7kmph
Source: SSC CHSL 2020 (Tier-I) Prev. Year Paper (04-Aug-2021) (Shift 1) — prepp.in solved paper · reliable-secondary
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