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SSC CHSL 2016 · Question 155 of 188

Determine the value of  r 1 +  when r3 + s3 = 0 and r + s = 6 s

Simplification

  1. A0
  2. B0.5Correct
  3. C1
  4. D6

Answer: B. 0.5

Explanation

Given that r + s = 6 and r3 + s3 = 0 We have (r + s)3 = r3 + s3 + 3rs (r + s) ⇒ (6)3 = 0+3rs (6) ⇒ 6 ×6 × 6 = 12 rs = 3×6 Now, 1 1 r+s 6 1 + = = = = 0.5 r s rs 12 2 Sum = Average = x× \ Radius = ⇒x= r1 C1 r2 C2 C. P. = New, from (i) and (ii) n1 : n2 : n3 = 2 : 3 : 3 393 × 100 = 15% 2620

Source: SSC CHSL Tier-I Solved Paper (5 March 2017, Shift-1) — Oswaal solved paper with answer key and explanations · reliable-secondary

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