SSC CHSL 2014 · Question 155 of 209
K¢ = (x – 25% of x) (y – 25% of y)2 2 æ öæ ö = 3y 27 xy 3x 2 = ç ÷ç ÷ 4 4 64 è øè ø æ ö 27 2 Value decreased by K – K¢ = - 1 xy ç ÷ 64 è ø 37 xy 2 = 64 2n æ ö R ç ÷ 2 = +
Source: SSC CHSL Solved Paper 16-11-2014 (Disha Publications) · reliable-secondary
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