SSC CHSL 2014 · Question 152 of 209
30° 45° B D C 10 m In DABC, tan 45° = AB BC AB Þ = = AB BC 1 ...(1) BC In DABD, tan 30° = AB BD 1 AB = BD 3 BD = AB 3 DC + BC = AB 3 - DC = AB 3 AB [from (i)] ( ) = - 10 AB 3 1 + ( ) 10 3 1 = ´ = + AB 5 3 1 m - + 3 1 3 1
Source: SSC CHSL Solved Paper 16-11-2014 (Disha Publications) · reliable-secondary
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