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SSC CHSL 2014 · Question 145 of 209

DIRECTIONS : In Question Nos. 96 to 100, a part of the sentence is The external fencing of a circular path around a circular plot of land is 33 m more than its interior fencing. The width of the path around the plot is

  1. A5.52 m
  2. B5.25 mCorrect
  3. C2.55 m
  4. D2.25 m 1 1 p , then value of x4 - 2x2 y2 + y4 is

Answer: B. 5.25 m

Explanation

Plot be r and R respectively. 2pR – 2pr = 33 m ´ Width of path, (R – r) = 33 7 21 = = 5.25m ´ 22 4 2 x4 – 2x2y2 + y4 = (x2 – y2)2 = [(x + y)(x – y)]2

Source: SSC CHSL Solved Paper 16-11-2014 (Disha Publications) · reliable-secondary

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