SSC CHSL 2014 · Question 123 of 209

DIRECTIONS : In Question Nos. 96 to 100, a part of the sentence is If q is a positive acute angle and 4 cos2 q – 4 cos q + 1 = 0, then the value of tan (q – 15°) is equal to

Answer: B. 1 1

(2 cos q – 1)2 = 0 2 cos q = 1 or, 1 q = Þ cos 2 q = 60° Hence, the value of tan (q – 15°) = tan (60° – 15°) = tan 45° = 1 2014 Solved Paper

Source: SSC CHSL Solved Paper 16-11-2014 (Disha Publications) · reliable-secondary

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SSC CHSL 2014 · Question 123 of 209

(2 cos q – 1)2 = 0 2 cos q = 1 or, 1 q = Þ cos 2 q = 60° Hence, the value of tan (q – 15°) = tan (60° – 15°) = tan 45° = 1 2014 Solved Paper

Source: SSC CHSL Solved Paper 16-11-2014 (Disha Publications) · reliable-secondary

Practice the full SSC CHSL 2014 paper

Timed test with all 209 questions, just like the real exam.