SSC CHSL 2013 · Question 144 of 207
Put x = sin q y = cos q in the above equation, we have 2 2 2 2 q + q = q + q sin cos sin cos Þ 1 = 1 Þ x = sinq & y = cosq is the solution of above equation. Now, on using x = sinq & y = cosq in 2 2 q q cos sin 1 + = 2 2 2 2 + a b x y
Source: SSC CHSL Solved Paper 20-10-2013 (Disha Publications) · reliable-secondary
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